locking actors together without constrains?
Hi, and thanks for looking. Problem-
player drives actor about on screen and bumps into other random objects (actors). These lock onto the player's actor and remain tracked onto it (imagine pie custard that sticks to one part of player's actor or spears that stick on various parts of large fruity body).
I can make this work with constraining the random objects to the actor with collision position offset to the player's position stored and updated in a game attribute, or by using 'move to' or 'move' in a similar way, but all of these methods are very heavy on the poor app (it appear not to slow the frame rate but the graphics seem to get sluggish). Any suggestions to alternative methods?
p.s. Even though the graphics are simple (currently), I don't want to hide all the possible variations of the sprite combinations in the player's actor as multiple images combined into a single graphic (there would millions of variations like grains of rice on a chess board multiplied from square to square).
Thanks for any input. Cheers Old Kipper
player drives actor about on screen and bumps into other random objects (actors). These lock onto the player's actor and remain tracked onto it (imagine pie custard that sticks to one part of player's actor or spears that stick on various parts of large fruity body).
I can make this work with constraining the random objects to the actor with collision position offset to the player's position stored and updated in a game attribute, or by using 'move to' or 'move' in a similar way, but all of these methods are very heavy on the poor app (it appear not to slow the frame rate but the graphics seem to get sluggish). Any suggestions to alternative methods?
p.s. Even though the graphics are simple (currently), I don't want to hide all the possible variations of the sprite combinations in the player's actor as multiple images combined into a single graphic (there would millions of variations like grains of rice on a chess board multiplied from square to square).
Thanks for any input. Cheers Old Kipper
Comments
cheers Kipper