Exp math help

laxking97

Okay so I'm working on a RPG and I need help haha.

Okay so the exp needed to level up is level³. So if you are level 100 then your exp is 100³, or 1,000,000.

Now the exp gain is 120 * (level of enemy)/5

So theres an enemy, lvl3 so
120 * 2/5
which comes out to 75 exp.

If my character is level 1 with 0 exp then that will level him up to 4 and 11 exp.

I'm wondering how I could put this as a rule(s). If someone helps me then I would be happy to share as a FREE template.

I KNOW THIS MIGHT BE HARD SO IF NO ONE HELPS IT WILL BE ALRIGHT

outasite

Exp formula:
[(n-1)^(10^(1+(n/10)))+b] * (1+(n/10)
n- current lvl
b- initial value

Examples:
level 1 {(0*10^1.1+100)*1.1=110}
level 2 {(1*10^1.2+100)*1.2=139}
level 3 {(2*10^1.3+100)*1.3=181}
level 4 {(3*10^1.4+100)*1.4=245}
level 5 {(4*10^1.5+100)*1.5=339}
Play with and alter as u like (depending on how big you want numbers to be).

For the enemies.
Attributes:
lvl: enemy level

{ [(lvl-1)^(10^(1+(lvl/10)))+b] * (1+(lvl/10) }

Examples:
level 1 {(0*2^1.1+20)*1.1=22}
level 2 {(1*2^1.2+20)*1.2=26}
level 3 {(2*2^1.3+20)*1.3=32}
level 4 {(3*2^1.4+20)*1.4=39}
level 5 {(4*2^1.5+20)*1.5=46}

outasite

outasite said:

[(n-1)^(10^(1+(n/10)))+b] * (1+(n/10)
Play with and alter as u like (depending on how big you want numbers to be).

I'd use the exp formula as a base for health. power, mana, money ect. for everything. Seems to make sense but idk.

outasite

Update: Formula v2.0

Hero Exp formula:
100^( 1+((n-1)/10) )

Examples:
level 1 {100^1.1 = 100}
level 2 {100^1.2 = 158}
level 3 {100^1.3 = 251}
level 4 {100^1.4 = 398}
level 5 {100^1.5 = 630}

Enemy Exp formula:
[ 100^( 1+((lvl-1)/10) ) ] / ((lvl-1)*2+4)

Examples:
level 1 {(100^1.1)/4 = 25}
level 2 {(100^1.2)/6 = 26}
level 3 {(100^1.3)/8 = 31}
level 4 {(100^1.4)/10 = 39}
level 5 {(100^1.5)/12 = 52}

The 4,6,8,10,12 is how many kills it takes to level.

Glossary:
n- current hero level
b- initial value
lvl- enemy level