For example you wouldn't want to spawn non-stop, have particles going at a spawn rate of 500, loop twice per frame, and have collide with high accuracy on with hundreds of actors.

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Your problem is here , adjust its position the way you want , x is horizontal and y is vertical. Horizontal should be self.position.x and vertical is a fixed number for the top edge.

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----Destroy

--Destroy

My hero collects these static coins and I have set up a destroy actor behaviour for them to disappear,

Elegant solution above.

Let's say you're using game.HighScore to store the player's high score. Which attribute you use doesn't really matter as long as it's one that will definitely be set to something if the player owns th

Something like first 50% are free than you have to pay. Always have a banner ticking at bot or top until the player buys the full game.

Just as the title says I'm hosting a Top Score Summer Game Contest with a game I Developed / re-skinned on Gamesalad. They have amazing templates up on GsHelper.com check them out!

Sadly the sate of the App Stores is that most paid games don't do well (financially) by default. People have been conditioned to expect their games, event top quality games, to be free. Which is sad a

different values (and an exit button) spawn on top of that.

I haven't tried this. It might work.

The idea is to lock the camera to the screen size to the game wont be zoomed/shifted/unplayable. No movable players, just a top down static camera.

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To destroy the coins that the hero has missed you can place a wall outside the screen and when the coins collide with the wall, destroy the coins.

The Animation behaviour and the Timer behaviour are both fine for everyday animation duties, but they top out at 30fps, I prefer to use either Constrain or Loop because they work at the code cycle spe

I would imagine that this will have to be done with my spawning actors as it would crash the game otherwise. If the visible game screen width is 667, destroy actor if it is 333.5px away relative to th

Multiply multiplies the value of the pixel in the layer set to 'multiply' by the underlying pixel and then divides the result by 255.